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Sagot :
Given:
[tex]\text{The primary voltage is V}_p=240\text{ V}[/tex][tex]\text{The secondary voltage is V}_s=12\text{ V}[/tex][tex]\text{The primary current is I}_p=10\text{ A}[/tex]The initial number of tun is,
[tex]n_p=5000[/tex]A.
from the formula of transformer,
[tex]\begin{gathered} \frac{I_s}{I_p}=\frac{n_p}{n_s} \\ \frac{180\text{ A}}{10\text{ A}}=\frac{5000}{n_s} \\ n_s=\frac{5000\times10}{180} \\ n_s=278 \end{gathered}[/tex]B.
Output of the transformer is,
[tex]\begin{gathered} P_{out}=V_sI_s \\ =12\text{ V}\times180\text{ A} \\ =2160\text{ Watt} \end{gathered}[/tex]Hence the output power is 2160 Watt.
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