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Sagot :
Let's investigate whether two pairs of corresponding angles in two triangles having equal angle measures is necessary and sufficient to prove that the triangles are similar.
Let's first create a random triangle ABC:
From triangle ABC, we have:
m∠ABC = 88 degrees
m∠CAB = 32 degrees
Apply the Triangle Angle Sum to find m∠ACB:
180 - 88 - 32 = 60 degrees
Hence, we have:
m∠ACB = 60 degrees.
Now, for triangle DEF, we have:
m∠DEF = 88 degrees
m∠FDE = 32 degrees
Also, the measure of angle EFD will be:
180 - 88 - 32 = 60 degrees
m∠EFD = 60 degrees
Part C.
We can see the corresponding angles of ∆DEF and ∆ABC are congruent, although the corresponding side lengths of not equal.
Part D.
We have the measures of the correspoding angles:
m∠ABC = m∠DEF = 88 degrees
m∠CAB = m∠FDE= 32 degrees
The angles we did not set in triangle DEF is:
m∠EFD = 60 degrees
Now, the corresponding angle to angle EFD is:
Angle ACB = 60 degrees.
Part E.
With the two angles, fixed, we can see that using the two angles fixed and completing the triangles, both triangles have similar shapes.
Part F. Since the corresponding angles of the triangles are congruent, the corresponding side lengths will be the proportion.
The ratios of the corresponding sides will be equal.
Part G:
Let:
AC = 8
AB = 6
BC = 4
DF = 4
DE = 3
EF = 2
Let's dilate using scale factor = 2
AC = 8 * 2 = 16
Ab = 6 * 2 = 12
BC = 4 * 2 = 8
Now, let's compare the corresponding sides:
[tex]\begin{gathered} \frac{AC}{DF}=\frac{16}{4}=4 \\ \\ \frac{AB}{DE}=\frac{12}{3}=4 \\ \\ \frac{BC}{EF}=\frac{8}{2}=4 \end{gathered}[/tex]We can see that after dilating ABC about the origin, the ratio of the corresponding sides are constant.
This means the corresponding sides of ABC and DEF are still in proportion.
Part H.
Based on their lengths and angle measures, we can say the triangles are Similar triangles.
Similar triangles have corresponding congruent angles and the corresponding sides are in proportion.
Part I.
The sequence of transformation that can be used here is the dilation, rotation, and translation.
Part J.
Both triangles are similar.
Part K.
Yes, knowing two pairs of corresponding angles are equal is enough to know to decide that two triangles are similar.
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