Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

AA Criterion for Similar Triangles, Part 2As you saw in the previous activity, knowing that one pair of corresponding angle measures in two triangles is equal is not enough to prove that they are similar. Some additional information must be required to prove triangle similarity. Next you’ll investigate whether two pairs of corresponding angles in two triangles having equal angle measures is necessary and sufficient to prove that the triangles are similar. Open GeoGebra again, and complete each step below.Part ACreate a random triangle, ∆ABC. Measure and record its angles.Choose two of the angles on ∆ABC, and locate the line segment between them. Draw a new line segment, , parallel to the line segment you located on ∆ABC. You can draw of any length and place it anywhere on the coordinate plane, but not on top of ∆ABC.From points D and E, create an angle of the same size as the angles you chose on ∆ABC. Then draw a ray from D and a ray from E through the angles such that the rays intersect. You should now have two angles that are congruent to the angles you chose on ∆ABC.Label the point of intersection of the two rays F, and draw ∆DEF by creating a polygon through points D, E, and F.Take a screenshot of your results, save it, and insert the image in the space below.Record all three angle measurements of ∆DEF in the table below. Angle∠DEF∠EFD∠FDE measurementsPart DHow do the angles of ∆DEF compare with those in the original triangle? In particular, compare the angle that you did not set in ∆DEF with the Part EWith two of the angles fixed on ∆DEF, what do you notice about the shape of ∆DEF when compared with ∆ABC?Pick any side of ∆DEF, and find its length. Find the ratio (n) of this side to the corresponding side of ∆ABC.Dilate ∆ABC about the origin using the scale factor n. Measure and compare the lengths of the sides of the dilated triangle, ∆A'B'C', with those of ∆DEF. Take a screenshot of your dilation, save it, and insert the image below the table.What can you conclude about ∆A'B'C' and ∆DEF based on their side lengths, angle measures, or both?Explain why there must be a sequence of rigid transformations that will map ∆A'B'C' exactly onto ∆DEF. Find and perform one such sequence of rigid transformations. Describe the sequence of rigid transformations you performed.Part JBased on your responses to parts H and I, what can you conclude about ∆ABC and ∆DEF? Explain your answer in terms of similarity transformations.Part KTo decide whether two triangles are similar, is it enough to know that two pairs of corresponding angle measures in the triangles are equal? Use your observations and your understanding of similarity to explain your answer.

Sagot :

Let's investigate whether two pairs of corresponding angles in two triangles having equal angle measures is necessary and sufficient to prove that the triangles are similar.

Let's first create a random triangle ABC:

From triangle ABC, we have:

m∠ABC = 88 degrees

m∠CAB = 32 degrees

Apply the Triangle Angle Sum to find m∠ACB:

180 - 88 - 32 = 60 degrees

Hence, we have:

m∠ACB = 60 degrees.

Now, for triangle DEF, we have:

m∠DEF = 88 degrees

m∠FDE = 32 degrees

Also, the measure of angle EFD will be:

180 - 88 - 32 = 60 degrees

m∠EFD = 60 degrees

Part C.

We can see the corresponding angles of ∆DEF and ∆ABC are congruent, although the corresponding side lengths of not equal.

Part D.

We have the measures of the correspoding angles:

m∠ABC = m∠DEF = 88 degrees

m∠CAB = m∠FDE= 32 degrees

The angles we did not set in triangle DEF is:

m∠EFD = 60 degrees

Now, the corresponding angle to angle EFD is:

Angle ACB = 60 degrees.

Part E.

With the two angles, fixed, we can see that using the two angles fixed and completing the triangles, both triangles have similar shapes.

Part F. Since the corresponding angles of the triangles are congruent, the corresponding side lengths will be the proportion.

The ratios of the corresponding sides will be equal.

Part G:

Let:

AC = 8

AB = 6

BC = 4

DF = 4

DE = 3

EF = 2

Let's dilate using scale factor = 2

AC = 8 * 2 = 16

Ab = 6 * 2 = 12

BC = 4 * 2 = 8

Now, let's compare the corresponding sides:

[tex]\begin{gathered} \frac{AC}{DF}=\frac{16}{4}=4 \\ \\ \frac{AB}{DE}=\frac{12}{3}=4 \\ \\ \frac{BC}{EF}=\frac{8}{2}=4 \end{gathered}[/tex]

We can see that after dilating ABC about the origin, the ratio of the corresponding sides are constant.

This means the corresponding sides of ABC and DEF are still in proportion.

Part H.

Based on their lengths and angle measures, we can say the triangles are Similar triangles.

Similar triangles have corresponding congruent angles and the corresponding sides are in proportion.

Part I.

The sequence of transformation that can be used here is the dilation, rotation, and translation.

Part J.

Both triangles are similar.

Part K.

Yes, knowing two pairs of corresponding angles are equal is enough to know to decide that two triangles are similar.

View image KelceyM522798