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Sagot :
Answer:
The [OH−] is 3.7x10-7M.
Explanation:
1st) Using the pH value (7.57) and the relation between pH and pOH, we have to calculate the pOH of the blood plasma:
[tex]\begin{gathered} pH+pOH=14 \\ 7.57+pOH=14 \\ pOH=14-7.57 \\ pOH=6.43 \\ \end{gathered}[/tex]2nd) Now with the pOH value (6.43) and the formula of pOH, we can calculate the [OH−] :
[tex]\begin{gathered} pOH=-log\lbrack OH^-\rbrack \\ 6.43=-log\lbrack OH^-\rbrack \\ 10^{(-6.43)}=\lbrack OH^-\rbrack \\ 3.7*10^{-7}M=\lbrack OH^-\rbrack \end{gathered}[/tex]So, the [OH−] is 3.7x10-7M.
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