At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
[tex]\begin{gathered} y=\frac{1}{3x}+4\ldots\ldots\ldots\ldots\ldots equation\text{ 1} \\ y=2x-1\ldots\ldots\ldots\ldots\ldots\text{equation 2} \\ \end{gathered}[/tex]
Step 1: We equation 1 to equation 2
[tex]\begin{gathered} \frac{1}{3x}+4=2x-1 \\ mulltiply\text{ through by 3x, we have;} \\ 1+12x=6x^2-3x \\ 6x^2-3x-12x-1=0 \\ 6x^2-15x-1=0 \\ \end{gathered}[/tex]Step 2: We apply the quadratic formula to solve the equation above to get two pairs of solution for x;
[tex]\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where a= 6, b=-15 , c= -1} \\ x=\frac{-(-15)\pm\sqrt[]{(-15)^2-4(6)(-1)}}{2(6)} \\ x=-0.06\text{ or x = }2.56 \end{gathered}[/tex]So, we have gotten solutions for x, let's proceed for y;
Step 3: For each value of x, we will solve for a corresponding value for y;
[tex]\begin{gathered} \text{When x=-0.06;} \\ y=2x-1 \\ y=2(-0.06)-1 \\ y=-1.12 \\ \text{When x=2.56;} \\ y=2(2.56)-1 \\ y=4.12 \end{gathered}[/tex]Hence, the ordered pairs of the solution are (-0.06, -1.12) and (2.56, 4.12)
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.
