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Sagot :
The given number is : 8,622,222
Since, there are 7 digits total, Normally the arrangenments of 7 distinct elements are 7!
But in the given number, there are five 2 digit number and one 8 digit number as well as one 6 digit number
From the properties of Permutation: The arrangement of p and q similar elements out of total n elements the arrangements are : n!/p! q!
[tex]\begin{gathered} \text{ Permutation of 8622222=}\frac{7!}{5!} \\ \text{ Permutation of 8622222=}\frac{7\times6\times5!}{5!} \\ \text{ Permutation of 8622222=}\frac{7\times6\times1}{1} \\ \text{ Permutation of 8622222=}42 \end{gathered}[/tex]
Arrangements of 8,622,222 digits are 42
Answer : 42 arrangements
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