Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

What is the mass, in grams, of 5.67 x 10 24 molecules of cobalt ( II ) chloride, CoCl2?Select one:a.3,420.1 gb.1,222.5 gc.129.84 gd.2,190.8 g

Sagot :

In this question, we need to calculate the mass in grams of 5.67*10^24 molecules of CoCl2. The first thing we need to do is to find the number of moles that we have in this amount of molecules, in order to do so, we use the Avogadro's number, which is 6.02 * 10^23 molecules in 1 mol:

6.02*10^23 molecules = 1 mol

5.67*10^24 molecules = x moles

6.02*10^23x = 5.67*10^24

x = 5.67*10^24/6.02*10^23

x = 9.418 moles of CoCl2 in 5.67*10^24 molecules

Now that we have the number of moles, 9.418, we can calculate the mass, using the molar mass of CoCl2, 129.84 grams/mol:

129.84 grams = 1 mol

x grams = 9.418 moles

x = 9.418 * 129.84

x = 1,222.5 grams

The answer will be letter B, 1,222.5g