Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

When (x^9 - x) is factored as completely as possible into polynomials and monomials with integral coefficients, how many factors are there?

When X9 X Is Factored As Completely As Possible Into Polynomials And Monomials With Integral Coefficients How Many Factors Are There class=

Sagot :

Notice that

[tex](x^9-x)=x(x^8-1)[/tex]

Furthermore,

[tex](x^8-1)=(x^4+1)(x^4-1)=(x^4+1)(x^2+1)(x^2-1)=(x^4+1)(x^2+1)(x+1)(x-1)[/tex]

Then,

[tex](x^9-x)=x(x^4+1)(x^2+1)(x+1)(x-1)[/tex]

This expression cannot be further simplified. There are 5 factors in total, one monomial and four binomials.

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.