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What is the surface area of the box,in square meters,that Isaiah decorates?

What Is The Surface Area Of The Boxin Square Metersthat Isaiah Decorates class=

Sagot :

To find the total surface area of the box, we have to find the area of each part.

Area of the two equal triangles.

[tex]A_{\text{triangles}}=2\frac{bh}{2}=bh[/tex]

Where b = 7m and h =8m.

[tex]A_{\text{triangles}}=7m\times8m=56m^2[/tex]

Now, let's find the area of each rectangle because they are different,

[tex]\begin{gathered} A_1=bh=13m\cdot7m=119m^2 \\ A_2=bh=13m\cdot8m=104m^2 \\ A_3=bh=13m\cdot10.63m=138.19m^2 \end{gathered}[/tex]

Then, we add all the areas

[tex]A_{\text{total}}=56+119+104+138.19=417.19m^2[/tex]

Hence, the total surface area is 417.19 square meters.

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