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Determine the period of the following trigonometric function.2παy = 2 sin(5)

Determine The Period Of The Following Trigonometric Function2παy 2 Sin5 class=

Sagot :

Given,

[tex]y=-2\sin (\frac{2\pi x}{5})[/tex]

To find the period,

[tex]\begin{gathered} y=-2\sin (\frac{2\pi x}{5}) \\ y=A\sin (Bx-c)+D \end{gathered}[/tex]

Then, the period is,

[tex]\begin{gathered} =\frac{2\pi}{B} \\ =\frac{2\pi}{\pi} \\ =2 \end{gathered}[/tex]

Thus the period is 2

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