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How many moles of Cr are there in a 92.3 g sample of chromium

Sagot :

To determine the number of moles, we look up in the periodic table the atomic weight of chromium, this is equal to 55.9961g/mol. And we apply the following relation:

[tex]\begin{gathered} Mo_{}lC_{}r=\text{Given g of Cr}\times\frac{1molCr}{\text{AtomicWeight, g Cr}} \\ Mo_{}lC_{}r=92.3\text{gCr}\times\frac{1molCr}{55.9961gCr}=1.6\text{mol Cr} \end{gathered}[/tex]

There are 1.6 moles of Cr in 92.3g sample

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