Answered

Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

i need help to solve it, be serious if you don't know don't answer please.

I Need Help To Solve It Be Serious If You Dont Know Dont Answer Please class=

Sagot :

[tex]k^2-8k+20=8[/tex][tex]k^2-8k+12=0[/tex][tex]k^2-8k=-12[/tex][tex]k^2-8k+16=-12+16[/tex][tex](k-4)^2=4[/tex]

then k-4=2 or k-4=-2

and we have that k=6 and k=2, are the two answers for the equation.

if we replace k=2 in the first equation

[tex](2)^2-8(2)+20=4-16+20=-12+20=8[/tex]

which makes the equation true for k=2, then is we replace k=6 in the first equation:

[tex](6)^2-8(6)+20=36-48+20=-12+20=8[/tex]

then the equation holds for k=6 too.

the second equation is:

[tex]2=\sqrt[]{-4-x}[/tex]

then

[tex]4=-4-x[/tex][tex]x=-4-4[/tex]

finally

[tex]x=-8[/tex]

if we replace x=-8 in the second equation

[tex]\sqrt[]{-4-(-8)}=\sqrt[]{-4+8}=\sqrt[]{4}=2[/tex]

then the equation holds for x=-8.

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.