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Sagot :
Given the line;
[tex]6x-3y+6=0[/tex]To find the y-intercept, we would make "y" the subject of the formula and compare the new equation with the general equation of a line.
[tex]\begin{gathered} 6x-3y+6=0 \\ 3y=6x+6 \\ 3y=3(2x+2) \\ Divid\text{ both sides by }3 \\ \frac{3y}{3}=\frac{3(2x+2)}{3} \\ y=2x+2 \end{gathered}[/tex]Recall that the equation of a line is given as;
[tex]y=mx+c[/tex]Where "m" is the gradient of the line and "c" is the y-intercept
By comparing both equations we would get the y-intercept(c) as;
[tex]c=2[/tex]Answer: Option A
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