At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
ANSWER
[tex]6y^6-15y^5-9y^4[/tex]EXPLANATION
We want to find the product of:
[tex]3y^4(2y\text{ + 1)(y - 3)}[/tex]To do this, let us first expand the two brackets. We do that by using the components in the first bracket to multiply the second:
[tex]\begin{gathered} 3y^4\lbrack(2y\cdot\text{ y) - (2y }\cdot\text{ 3) + (1 }\cdot\text{ y) + (1 }\cdot\text{ -3)\rbrack} \\ =\text{ }3y^4(2y^2\text{ - 6y + y - 3)} \end{gathered}[/tex]Now, expand this bracket by multiplying the term outside the bracket with those in it:
[tex]\begin{gathered} (3y^4\cdot2y^2)\text{ - (}3y^4\cdot\text{ 6y) + (}3y^4\cdot\text{ y) - }(3y^4\cdot\text{ 3)} \\ =\text{ }6y^{4\text{ + 2}}-18y^{4\text{ + 1}}+3y^{4\text{ + 1}}-9y^{4\text{ }} \\ =6y^6-18y^5+3y^5-9y^4 \\ =6y^6-15y^5-9y^4 \end{gathered}[/tex]That is the answer.
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.
