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Sagot :
y=5x +21
1) Since the line passes from (6,9) through (5,4) and has a slope of 5.
the slope-intercept form is given by y=mx +b
[tex]\begin{gathered} m=\frac{y_2-y_1_{}}{x_2-x_1} \\ m=\frac{4-9}{5-6} \\ m=\frac{-5}{-1} \\ m=5 \end{gathered}[/tex]Since the slope is 5, we can write:
y=5x +b
Pluggin in (5,4)
4=5(5)+b
4=25+b
4-25=25-25+b
21=b
b= 21
3) Finally, the slope-intercept form of this linear equation is y=5x +21
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