Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Let A = (5,-3) and B = (7,0). Notice that point A is the center of the circle, then:
[tex](h,k)=(5,-3)=A[/tex]now, point B is on the circumference of the circle, then, the distance between A and B is the radius of the circle:
[tex]\begin{gathered} r=d(A,B)=\sqrt[]{(5-7)^2+(-3-0)^2}=\sqrt[]{(-2)^2+(-3)^2}=\sqrt[]{4+9}=\sqrt[\square]{13} \\ \Rightarrow r=\sqrt[]{13} \end{gathered}[/tex]then, using the equation of the circle with center (h,k) and radius r:
[tex](x-h)^2+(y-k)^2=r^2[/tex]in this case, we have the following:
[tex]\begin{gathered} (h,k)=(5,-3) \\ r=\sqrt[]{13} \\ \Rightarrow(x-5)^2+(y-(-3))^2=(\sqrt[]{13})^2 \\ \Rightarrow(x-5)^2+(y+3)^2=13 \end{gathered}[/tex]therefore ,the equation of the circle is (x-5)^2 + (y+3)^2 = 13
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
