Answer:
The bank teller has 30 $5-bills and 5 $10-bills.
Explanation:
• Let the number of $5 bills = x
,• Let the number of $10 bills = y
The bank teller has a total of 35 bills.
[tex]\implies x+y=35\cdots(1)[/tex]The total value of the money is $200.
[tex]\begin{gathered} \text{The value of x \$5 bills = 5x} \\ \text{The value of y \$10 bills = 10y} \\ \implies5x+10y=200\cdots(2) \end{gathered}[/tex]We can divide equation (2) all through by 5:
[tex]\begin{gathered} \frac{5x}{5}+\frac{10y}{5}=\frac{200}{5} \\ x+2y=40\cdots(3) \end{gathered}[/tex]Solve equations (1) and (3) simultaneously:
[tex]\begin{gathered} x+2y=40\cdots(3) \\ x+y=35\cdots(1) \\ \text{Subtract } \\ y=5 \end{gathered}[/tex]Solve for x:
[tex]\begin{gathered} x+y=35 \\ x+5=35 \\ x=35-5 \\ x=30 \end{gathered}[/tex]x=30 and y=5
Thus, the bank teller has 30 $5-bills and 5 $10-bills.