Answer:
0.0731 moles of sucrose.
Explanation:
Let's see the structure of sucrose:
You can realize that the molecular formula of this compound is C12H22O11. This means that we have 12 carbons, 22 hydrogens, and 11 oxygens.
Remember that the molar mass of carbon is 12 g/mol, oxygen is 16 g/mol and hydrogen is 1 g/mol. So by doing an algebraic sum based on the molar masses of each element, we can find the molar mass of sucrose:
[tex]\begin{gathered} \text{Molar mass of sucrose = 12}\cdot\text{12}\frac{g}{mol}+22\cdot1\frac{g}{mol}+11\cdot16\frac{g}{mol}, \\ Mola\text{r mass of sucrose =}144\frac{g}{mol}+22\frac{g}{mol}+176\frac{g}{mol}, \\ Molar\text{ mass of sucrose =}342\text{ }\frac{g}{mol}. \end{gathered}[/tex]
Now that we have already found the molar mass of sucrose, we can do the conversion from 25 g of sucrose to moles using this molar mass, like this:
[tex]25\text{ g sucrose}\cdot\frac{1\text{ mol sucrose}}{342\text{ g sucrose}}=0.0731\text{ moles sucrose.}[/tex]
The answer is that we have 0.0731 moles of sucrose in 25 g of sucrose.
