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Sagot :
Given the following equation provided in the exercise:
[tex]x+6y=-36[/tex]You can solve for the variable "y" by following the steps shown below:
1. You must apply a property called "Subtraction property of equality". This states that:
[tex]\text{If }A=B,\text{ then }A-C=B-C[/tex]So you must subtract "x" from both sides of the equation:
[tex]\begin{gathered} x+6y-(x)=-36-(x) \\ 6y=-36-x \end{gathered}[/tex]2. Finally, you must apply the "Division property of equality". This states that:
[tex]\text{If }A=B,\text{ then }\frac{A}{C}=\frac{B}{C}[/tex]Then, dividing both sides of the equation by 6, you get the equation solved for "y" is:
[tex]\begin{gathered} \frac{6y}{6}=-\frac{36}{6}-\frac{x}{6} \\ \\ y=-\frac{x}{6}-6 \end{gathered}[/tex]
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