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Sagot :
We will determine the slope-intercept form of the points as follows:
First, we recall that the slope intercept form of a line is given by the expression:
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ \\ y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1) \end{gathered}[/tex]Where (x1, y1) & (x2, y2) are two points of the line, then:
[tex]\begin{gathered} y-2=(\frac{2-0}{0-(-4)})(x-0)\Rightarrow y-2=\frac{1}{2}(x-0) \\ \\ \Rightarrow y=0.5x+2 \end{gathered}[/tex]So, the equation of the line in slope intercept form is:
[tex]y=0.5x+2[/tex]
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