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Sagot :
Explanation:
Molarity is the ratio between the amount of substance in the solute, measured in mol (n1), and the volume of the solution in liters (V). This concentration is measured in mol per liter (mol/L).
The mathematical formula used to calculate this concentration is given by:
M = n1/V
First, we need to transform 0.589 g of MgI2 into moles. For this, we use the molar mass of MgI2.
Molar mass of Mg = 24.305 g/mol
molar mass of I = 126.90 g/mol
MgI2 = (1*24.305) + (2*126.90) = 278.1 g/mol
Now we use the following formula to transform grams to moles: moles = mass/molar mass
mass = 0.589 g
molar mass = 278.1 g/mol
moles = 0.589/278.1
moles = 2.1 x 10^-3
Now let's calculate the molarity:
n1 = 2.1 x 10^-3 moles
V = 75 mL = 0.075 L
M = 2.1 x 10^-3 /0.075
M = 0.0282 M
Answer: Alternative c. 0.0282 M
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