To answer this question we need to do the proper punnet square.
Alleles
Fawn: f
Less curled tail: T
Tight tail: t
Parental cross: ffTT x fftt
Gametes:
[tex]f\begin{cases}T=fT \\ T=fT\end{cases}f\begin{cases}t=ft \\ t=ft\end{cases}[/tex]
Punnet square
Phenotypic and genotypic frequencies
As we can see all the offspring obtained has the same genotype ffTt, therefore our genotypic and phenotypic frequencies are equal
fawn less curled tail ffTt: 16:16 = 16/16 = 1
So there is no possibility that a puppy with fawn hair and tight curl be born, the probability is 0%
