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Determine the molecular formula for the following compounds from the experimental data:80.0% carbon, 20% hydrogen, and a molecular mass of 30.0 amu

Sagot :

Answer

The molecular formula for the compound is C₂H₆

Explanation

Given:

% composition: 80.0% carbon, 20% hydrogen.

Molecular mass = 30.0 amu​

What to find:

The molecular formula for the compound.

Step-by-step solution:

Assume we have 100 grams total of the substance.

Grams C: 80.0/100 x 100 g = 80.0 g

Grams H: 20/100 x 100 = 20 g

The next step is to convert the number of grams of each element into moles as shown below using the molar masses of H = 1.00784 g/mol and C = 12.011 g/mol.

Note: Mole = Mass/Molar mass.

Moles C = 80.0g/12.011 g/mol = 6.66 mol

Moles H = 20g/1.00784 g/mol = 19.84 mol

Now, let's divide the number of moles of each element by the smallest number obtained:

C = 6.66/6.66 = 1

H = 19.84/6.66 = 3

The empirical formula for the compound is CH

Using the molecular mass of 30.0 amu, the molecular formula is calculated as follows:

(Empirical mass)n = (Molecular mass)

(CH₃)n = 30.0

(12.011 + 3 x 1.00784)n = 30

(12.011 + 3.02352)n = 30

(15.03452)n = 30

Divide both sides by 15.03452

n = 2

Moleculare formula = (CH₃)₂ = C₂H₆

Therefore, the molecular formula for the compound is C₂H₆