Explanation.
To find the area of the figure, we will have to split the figure into different parts as following
We have 5 different parts
So the scope will be to find each of the areas and then sum them up
For part A
The area of a will be
[tex]Area_a=length\times breadth=17mi\times6mi=102mi^2[/tex]
For part B
Area of B will be found to be
[tex]Area_b=length\times breadth=19mi\times6mi=114mi^2[/tex]
Part C
The figure is a quadrant
The area of a quadrant is
[tex]Area_c=\frac{1}{4}\pi r^2=\frac{1}{4}\times3.14\times11^2=94.99mi^2[/tex]
For part D
The figure is a rectangle
The area of the rectangle
[tex]Area_d=length\times breadth=19mi\times5mi=95mi^2[/tex]
Finally for part E
We will find the area of the triangle
[tex]Area_e=\frac{1}{2}\times base\times area=\frac{1}{2}\times4mi\times3mi=6mi^2[/tex]
The area of the figure is the sum of all values of A, B, C, D, and E
[tex]\begin{gathered} Area=102+114+94.99+95+6 \\ Area=411.99mi^2 \\ Area=412mi^2 \end{gathered}[/tex]
The area of the figure is approximately 412 square miles
