Answered

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Consider functions fand g.I + 122 + 41 – 12for 1 * 2 and r * -64.12A g(t) =16.1 + 1641 + 48for r # -123Which expression is equal to f(x) · g()O A.A.4781I + 6I – 2I + 6OC.D.I + 2I – 6

Consider Functions Fand GI 122 41 12for 1 2 And R 6412A Gt 161 1641 48for R 123Which Expression Is Equal To Fx GO AA4781I 6I 2I 6OCDI 2I 6 class=

Sagot :

Given,

[tex]\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}[/tex]

To find the value of f(x) . g(x):

[tex]\begin{gathered} f(x)\times g(x)=\frac{x+12}{x^2+4x-12}\times\frac{4(x^2-4x+4)}{4(x+12)} \\ =\frac{x^2-4x+4}{x^2+4x-12} \\ =\frac{(x-2)(x-2)}{(x-2)(x+6)} \\ =\frac{(x-2)}{(x+6)} \end{gathered}[/tex]

Thus the solution is,

[tex]f(x)\cdot g(x)=\frac{(x-2)}{(x+6)}[/tex]

The answer is option-c

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