Answered

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If ABCD is dilated by afactor of1/3, thecoordinate of A' would be:

If ABCD Is Dilated By Afactor Of13 Thecoordinate Of A Would Be class=

Sagot :

SOLUTION:

The coordinates of A are;

[tex](-3,-3)[/tex]

When this is dilated by a factor of 1/3, the new coordinates of A are;

[tex]A^{\prime}=(-1,-1)[/tex]

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