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Sagot :
Answer:
Explanation:
Let the cost of delivering a small box = s
A large box costs $3 more than a small box, therefore:
• The cost of delivering a large box = s+3
There are 8 small boxes and 5 large boxes.
• The cost of 8 small boxes = 8s
,• The cost of 5 large boxes =5(s+3)
Since the total charge for the boxes is $184.
[tex]8s+5\mleft(s+3\mright)=184[/tex]We then solve for s.
[tex]\begin{gathered} 8s+5s+15=184 \\ 13s=184-15 \\ 13s=169 \\ s=\frac{169}{13} \\ s=\$13 \end{gathered}[/tex]The cost of delivering a small box =$13.
Therefore, the cost of delivering a large box =13+3 =$16
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