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I solved this problems already. Just want to see if I got it correct.

I Solved This Problems Already Just Want To See If I Got It Correct class=

Sagot :

Given the statement:

y varies directly as the cube of x.

When: x = 6, y = 36

Let's find the constant of variation and the variation equation.

Here, we are to solve using the direct variation equation:

y = kx

Where k is the constat of variation.

To find the constant of variation, k, substitute 6 for x and 36 for y.

Thus, we have:

y = kx

36 = 6k

Divide both sides of the equation by 6:

[tex]\begin{gathered} \frac{36}{6}=\frac{6k}{6} \\ \\ 6=k \\ \\ k=6 \end{gathered}[/tex]

Therefore, the constant of variation is = 6.

The varitaion equation will be:

y = 6x

ANSWER:

• k = 6

• Variation equation,: ,y = 6x

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