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Sagot :
The slope intercept form is
[tex]y=mx+b[/tex]Where
b is the y-coordinate of the y-intercept
m is the slope of the line
To determine the equation given that we know the slope and one point of the line you have to use the point slope form
[tex]y-y_1=m(x-x_1)[/tex]m=1/4, and point (12,-3)
[tex]\begin{gathered} y-(-3)=\frac{1}{4}(x-12) \\ y+3=\frac{1}{4}x-3 \\ y=\frac{1}{4}x-3-3 \\ y=\frac{1}{4}x-6 \end{gathered}[/tex]The equation of the line with slope 1/4 that crosses the point (12,-3) in slope intercept form is:
[tex]y=\frac{1}{4}x-6[/tex]
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