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hypotenuse: 20 mmleg1=12 mmleg2=?What is the length of the missing leg in this right triangle?

Sagot :

16 mm

Explanation

Step 1

we have a rigth triangle so we can use the Pythagoras theorem

[tex]\begin{gathered} \text{leg}^{^2}_1+leg_2^2=potenuse^2 \\ \text{replacing} \\ 12^2+leg^2=20^2 \\ 144+Leg^2=400 \\ \text{subtract 144 in both sides} \\ 144+\text{leg}^2-144=400-144 \\ \text{leg}^2=256 \\ \text{leg}=\sqrt[]{256} \\ \text{leg}=16 \end{gathered}[/tex]

I hope this help you