SOLUTION
Given the question, the following are the solution steps to answer the question.
STEP 1: Get the number of possible outcomes for rolling a pair of dice.
The number of possible outcome of rolling a single die is 6, rolling two dice means the number of outcomes will be squared. Therefore, the number of total outcomes will be 36.
STEP 2: Draw a table of the possible outcomes from rolling two dice
STEP 3: Draw a table for the sum of the outcomes of the two dice
We sum the outcome in the table in Step 2 to have a new table below;
STEP 4: Select the outcomes that have a sum of 8
STEP 5: Select the outcomes that have a sum of 11
STEP 6: Get the probability of sum of 8
[tex]\begin{gathered} Pr(sum\text{ of 8\rparen}\Rightarrow\frac{number\text{ of outcomes of 8}}{total\text{ outcomes}} \\ Pr(sum\text{ of 8\rparen}\Rightarrow\frac{5}{36} \end{gathered}[/tex]STEP 7: Get the probability of sum of 11
[tex]\begin{gathered} Pr(su\text{m of 11\rparen}\Rightarrow\frac{number\text{ of outcomes of 11}}{total\text{ outcomes}} \\ \\ Pr(sum\text{ of 11\rparen}\Rightarrow\frac{2}{36} \end{gathered}[/tex]STEP 8: Get the odds that the sum is 8 or 11If you don’t need any further explanation, I’ll go ahead and end our session. Remember the answer is saved in your profile. Feel free to let me know how I did by rating our session. I would appreciate your feedback. You can provide it by rating the session. Thanks, and have a great day!
[tex]\begin{gathered} Pr(A\text{ or B\rparen}\Rightarrow Pr(A)+Pr(B) \\ Pr(8\text{ or 11\rparen}\Rightarrow Pr(8)+Pr(11) \\ \Rightarrow\frac{5}{36}+\frac{2}{36}=\frac{5+2}{36}=\frac{7}{36} \\ \\ odds\text{ is given as cjhance of event occuring against event not occuring} \\ 36-7=29 \end{gathered}[/tex]
Hence, the odds that the sum is 8 or 11 is 7 to 29 or 7/36
