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I need help with this problem. The points (2,a) and (-4,-10) fall on a line with a slope of 8. What is the value of a?

I Need Help With This Problem The Points 2a And 410 Fall On A Line With A Slope Of 8 What Is The Value Of A class=

Sagot :

Given the word problem, we can deduce the following information:

1. Points (2,a) and (-4,-10).

2. Slope = 8

To determine the value of a, we use the formula:

[tex]\text{slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]

Based on the given values, we let:

[tex]\begin{gathered} x_1=2 \\ y_1=a \\ x_2=-4 \\ y_2=-10 \end{gathered}[/tex]

We plug in what we know:

[tex]\begin{gathered} \text{slope}=\frac{y_2-y_1}{x_2-x_1} \\ 8=\frac{-10-a}{-4-2} \\ \text{Simplify and rearrange} \\ 8=\frac{-10-a}{-6} \\ 8(-6)=-10-a \\ -48=-10-a \\ a=-10+48 \\ \text{Calculate} \\ a=38 \end{gathered}[/tex]

Therefore, the value of a is 38.