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Confidence intervals for MeansMay 09, 9:42:28 PMn.A study by the department of education of a certain state was trying todetermine the mean SAT scores of the graduating high school seniors.The study examined the scores of a random sample of 212 graduatingseniors and found the mean score to be 449 with a standard deviationof 80. Determine a 95% confidence interval for the mean, rounding allvalues to the nearest tenth.Submit Answerattempt 1 out of 2

Sagot :

The 95% confidence interval of the mean is

[tex]\begin{gathered} 449\text{ }\pm11 \\ (438,\text{ 460)} \end{gathered}[/tex]

It is calculate by

[tex]\begin{gathered} \bar{x}\text{ }\pm\text{ Z}\frac{s}{\sqrt[]{n}} \\ \end{gathered}[/tex]

where x is the mean (449), Z is chosen Z value ( 2 for 95%), s is the standard deviation (80), and n is the number of observation (212)

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