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The admission fee at an amusement park is $4.25 for children and $7.20 for adults. On a certainday, 333 people entered the park, and the admission fees collected totaled $1843. How manychildren and how many adults were admitted?

Sagot :

Given:

The admission fee at an amusement park is $4.25 for children and $7.20 for adults.

Let the number of children = x

Let the number of adults = y

On a certain day, 333 people entered the park

so, we have the following equation:

[tex]x+y=333\rightarrow(1)[/tex]

And, the admission fees collected totaled $1843

so, the equation will be:

[tex]4.25x+7.2y=1843\rightarrow(2)[/tex]

We will solve the equations (1) and (2)

From equation (1):

[tex]x=333-y\rightarrow(3)[/tex]

substitute with (x) from equation (3) into equation (2):

[tex]4.25\cdot(333-y)+7.2y=1843[/tex]

solve the equation to find y:

[tex]\begin{gathered} 4.25\cdot333-4.25y+7.2y=1843 \\ -4.25y+7.2y=1843-4.25\cdot333 \\ 2.95y=427.75 \\ y=\frac{427.75}{2.95}=145 \end{gathered}[/tex]

Substitute with (y) into equation (3) to find the value of (x):

[tex]x=333-145=188[/tex]

So, the answer will be:

The number of children = x = 188

The number of adults = y = 145