Perimete23.33 feet
Explanation:
A room is like a rectngle. SO we would apply the perimeter of a rectangle
perimeter of a rectangle = 2(length + width)
length = 10'6" = 10 feet 6 inches
Width = 14' = 14 inches
Let's make the unit oof length and width to be in feet (that is the unit in the question option)
12 inches = 1 foot
6 inches = 6/12 = 1/2 feet
14 inches = 14/12 = 7/6 feet
length = 10 feet + 1/2 feet = 10 1/2 feet = 21/2 feet
width = 7/6 feet
perimeter of a rectangle = 2(21/2 + 7/6)
[tex]\begin{gathered} \text{perimeter = 2(}\frac{21}{2}+\text{ }\frac{7}{6})\text{ = 2(}\frac{3(21)+7)}{6} \\ \text{Perimeter = 2(}\frac{63+7}{6}) \end{gathered}[/tex][tex]\begin{gathered} \text{perimeter = 2(}\frac{70}{6})\text{ = 140/6} \\ \text{perimeter = 23.33 f}eet \end{gathered}[/tex]