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A pipe fitter must connect a pipeline to a tank as shown in the figure. The run from the pipeline to the tank is 64ft 6in., while the set (rise) is 35ft 9in. A. How long is the connection? B. Will the pipe fitter be able to use standard pipe fittings (I.e 22 1/2 degree, 30 degrees, 45 degrees, 60 degrees or 90 degrees?

A Pipe Fitter Must Connect A Pipeline To A Tank As Shown In The Figure The Run From The Pipeline To The Tank Is 64ft 6in While The Set Rise Is 35ft 9in A How Lo class=

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SOLUTION:

Step 1:

In this question, we are given the following:

A pipefitter must connect a pipeline to a tank as shown in the figure.

The run from the pipeline to the tank is 64ft 6in., while the set (rise) is 35ft 9in.

Step 2:

A. How long is the connection?

Converting 64 feet 6 inches to inches, we have that:

[tex]\text{( 64 x 12 ) + 6 = 768 + 6 = }774\text{ inches}[/tex]

Also, we have 35 feet 9 inches, we have that:

[tex](35\text{ x 12 ) + 9 = 420 + 9 = 429 inches}[/tex]

Using Pythagoras' Theorem, we have that:

[tex]\begin{gathered} l^2=(774)^2+(429)^2 \\ l^2\text{ = 599,076 + 184,041} \\ l^2\text{ = 783,117} \\ \text{square}-\text{root both sides, we have that:} \\ \text{l =884.93} \\ l\approx\text{ 885 inches ( to the nearest inches)} \\ l\text{ = 73 ft 9 inches} \end{gathered}[/tex]

The length of the connection = 73 feet 9 inches

Step 3:

Will the pipe fitter be able to use standard pipe fittings?

From the diagram, we can see that:

[tex]\begin{gathered} tan\text{ }\theta\text{ =}\frac{774\text{ inches ( opposite)}}{429\text{ inches (adjacent)}} \\ \tan \text{ }\theta\text{ = 1.8042} \\ \theta\text{ =}\tan ^{-1}\text{ (1.8042)} \\ \theta\text{ = 61.00 degre}es\text{ } \\ \theta\approx\text{ 60 degr}ees\text{ ( to the nearest degre}e) \end{gathered}[/tex]

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