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What is the electric force between à -0.02 C charge and a 0.03 C charge separated by 2.4meters?

Sagot :

Given:

The charges;

q₁=-0.02 C

q₂=0.03 C

The separation between the charges, r=2.4 m

To find:

The electric force between the charges.

Explanation:

From Coulomb's law,

[tex]F=\frac{k|q_1||q_2|}{r^2}[/tex]

Where k is the Coulomb's constant.

On substituting the known values,

[tex]\begin{gathered} F=\frac{9\times10^9\times0.02\times0.03}{2.4^2} \\ =937.5\times10^3\text{ N} \\ =937.5\text{ kN} \end{gathered}[/tex]

Final answer:

The electric force between the charges is 937.5 kN.