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If I release a golf ball at a height of 31 cm and a length of 31 cm the mass is equal to 45.93 g what is theKinetic energy

Sagot :

When a ball is at a particular height it possess potential energy which is given as,

[tex]U=\text{mgh}[/tex]

The potential energy is converted into kinetic energy of the ball. According to conservation of energy,

[tex]K=U[/tex]

which can be further given as,

[tex]K=\text{mgh}[/tex]

Substitute the known values,

[tex]\begin{gathered} K=(45.93\text{ g)(}\frac{1\text{ kg}}{1000\text{ g}})(9.8m/s^2)(31\text{ cm)(}\frac{1\text{ m}}{100\text{ cm}})(\frac{1\text{ J}}{1kgm^2s^{-2}^{}}) \\ =0.140\text{ J} \end{gathered}[/tex]

Thus, the kinetic energy of the ball is 0.140 J.