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21. How many 2 1/2 cans of pork and beans are required to serve 95 people if each can weighs 1 lbs. 10 oz. and each serving size is 6 ounces

Sagot :

Step 1

Convert 10 oz to pounds

[tex]10\text{ oz = }0.625\text{ pounds}[/tex]

Step 2

Find the total weight of a can of pork and beans in pounds

[tex]1\text{ + 0.625 = 1.625lbs}[/tex]

Step 3

Convert the weight of 1 can in pounds to ounces

[tex]1.625\text{lbs = }26\text{ ounces}[/tex]

Step 4

Find the weight of 5/2 cans of pork and beans.

[tex]\begin{gathered} \frac{1}{\frac{5}{2}}=\frac{26}{x} \\ x=\text{ 26}\times\frac{5}{2} \\ x=\text{ 65 ounces} \end{gathered}[/tex]

Step 5

Find the total weight of servings

[tex]\begin{gathered} \frac{1\text{ serving}}{95\text{ servings}}=\frac{6\text{ ounces}}{y} \\ y\text{ = 95 }\times6 \\ y\text{ = 570 ounces} \end{gathered}[/tex]

Step 6

Find how many 5/2 cans of pork needed for 95 people.

[tex]\begin{gathered} =\frac{570\text{ ounces}}{65\text{ ounces}}=\text{ }\frac{114}{13}\text{ 2}\frac{1}{2}\text{ cans} \\ \approx8.769\text{ 2}\frac{1}{2}cans \end{gathered}[/tex]

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