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Sagot :
ANSWER:
2.98 cm
STEP-BY-STEP EXPLANATION:
Given:
Length wire (L) = 6 m
Current (i) = 1.513 A
magnetic field (β) = 4.085 mT = 4.085 x 10^-3 T
Magnetic field at the center of circular coil is given for the following formula:
[tex]\beta=\frac{\mu_0\cdot N\cdot i}{2R}=\frac{\mu_0\cdot N\cdot\imaginaryI}{d}[/tex]The total length of wire in the coil is given by:
[tex]\begin{gathered} L=\pi\cdot d\cdot N \\ \\ N=\frac{L}{\pi d} \end{gathered}[/tex]We replacing:
[tex]\begin{gathered} \beta=\frac{\mu_0\cdot\frac{L}{\pi d}\cdot\imaginaryI}{d} \\ \\ \beta=\frac{\mu_0\cdot L\cdot\imaginaryI}{\pi\cdot d^2} \\ \\ d^2=\frac{\mu_0\cdot L\cdot\imaginaryI}{\pi\beta} \\ \\ d=\sqrt{\frac{\mu_0L\imaginaryI}{\pi\beta}} \\ \\ \text{ Therefore:} \\ \\ d=\sqrt{\frac{4\pi\cdot10^{-7}\cdot6\cdot1.513}{\pi\cdot4.085\cdot10^{-3}}} \\ \\ d=0.0298\text{ m}=2.98\text{ cm} \end{gathered}[/tex]Therefore, the diameter in centimeters is equal to 2.98 cm
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