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Sagot :
To find the mass of 52.3 L of Fe₂O₃ we have to convert those L into moles, and then the moles into grams.
We know that 1 mol of an ideal gas (at STP) occupies 22.4 L. We can use that conversion to find the number of moles.
moles of Fe₂O₃ = 52.3 L * 1 mol/(22.4 L)
moles of Fe₂O₃ = 2.33 moles
Now we can convert those moles into grams using the molar mass of Fe₂O₃.
atomic mass of Fe = 55.85 amu
atomic mass of O = 16.00 amu
molar mass of Fe₂O₃ = 2 * 55.85 + 3 * 16.00
molar mass of Fe₂O₃ = 159.7 g/mol
mass of Fe₂O₃ = molar mass of Fe₂O₃ * moles of Fe₂O₃
mass of Fe₂O₃ = 159.7 g/mol * 2.33 moles
mass of Fe₂O₃ = 372 g
Answer: the mass of 52.3 L of Fe₂O₃ is 372 g.
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