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i need help on all these questionsFind the equation of the lineHelp with number 10

I Need Help On All These QuestionsFind The Equation Of The LineHelp With Number 10 class=

Sagot :

Answer:

y = (8/7)x + 33/7

Explanation:

First, we need to calculate the slope of the line. So, we can use the following equation:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Where (x1, y1) and (x2, y2) are the coordinates of two points in the line.

We can replace (x1, y1) with (-5, -1) and (x2, y2) with (2, 7) and get that the slope is equal to:

[tex]m=\frac{7-(-1)}{2-(-5)}=\frac{7+1}{2+5}=\frac{8}{7}[/tex]

Now, the equation of a line with slope m that passes through the point (x1, y1) is:

[tex]y-y_1=m(x-x_1)[/tex]

So, replacing m by 8/7 and (x1, y1) by (-5, -1), we get that the equation is:

[tex]\begin{gathered} y-(-1)=\frac{8}{7}(x-(-5)) \\ y+1=\frac{8}{7}(x+5) \end{gathered}[/tex]

Finally, we can solve the equation for y and get:

[tex]\begin{gathered} y+1=\frac{8}{7}x+\frac{8}{7}(5) \\ y+1=\frac{8}{7}x+\frac{40}{7} \\ y+1-1=\frac{8}{7}x+\frac{40}{7}-1 \\ y=\frac{8}{7}x+\frac{33}{7} \end{gathered}[/tex]

Therefore, the answer is:

y = (8/7)x + 33/7

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