Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
ANSWER
3.79×10⁵ m/s
EXPLANATION
Given:
• The potential difference, ΔV = 750 V
,• The mass of the proton, mp = 1.67*10⁻²⁷ kg
,• The electric charge of a proton, e = 1.60*10⁻¹⁹ C
Unknown:
• The final velocity of the proton, v
The kinetic energy of the proton at the end of the motion is,
[tex]KE=\frac{1}{2}m_pv^2[/tex]This kinetic energy is obtained from the work done to move the proton,
[tex]W=e\cdot\Delta V[/tex]By conservation of energy,
[tex]\frac{1}{2}m_pv^2=e\cdot\Delta V[/tex]Solving for v,
[tex]v=\sqrt[]{\frac{2\cdot e\cdot\Delta V}{m_p}}[/tex]Replace with the known values and solve,
[tex]v=\sqrt[]{\frac{2\cdot1.60\times10^{-19}C\cdot750V}{1.67\times10^{-27}kg}}\approx3.79\times10^5m/s[/tex]Hence, the final velocity of the proton is 3.79 × 10⁵ m/s.
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.
