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Sagot :
ANSWER
3.79×10⁵ m/s
EXPLANATION
Given:
• The potential difference, ΔV = 750 V
,• The mass of the proton, mp = 1.67*10⁻²⁷ kg
,• The electric charge of a proton, e = 1.60*10⁻¹⁹ C
Unknown:
• The final velocity of the proton, v
The kinetic energy of the proton at the end of the motion is,
[tex]KE=\frac{1}{2}m_pv^2[/tex]This kinetic energy is obtained from the work done to move the proton,
[tex]W=e\cdot\Delta V[/tex]By conservation of energy,
[tex]\frac{1}{2}m_pv^2=e\cdot\Delta V[/tex]Solving for v,
[tex]v=\sqrt[]{\frac{2\cdot e\cdot\Delta V}{m_p}}[/tex]Replace with the known values and solve,
[tex]v=\sqrt[]{\frac{2\cdot1.60\times10^{-19}C\cdot750V}{1.67\times10^{-27}kg}}\approx3.79\times10^5m/s[/tex]Hence, the final velocity of the proton is 3.79 × 10⁵ m/s.
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