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What is the value of X-intercept of the function below? 3y=- 6/4 (x+4)+12

What Is The Value Of Xintercept Of The Function Below 3y 64 X412 class=

Sagot :

We are given the equation:

[tex]3y=-\frac{6}{4}(x+4)+12[/tex]

We need to solve the equation for the x-intercept. We first need to simplify the given equation into slope-intercept form.

[tex]\begin{gathered} \frac{3y}{3}=\frac{-\frac{6}{4}(x+4)+12}{3} \\ \\ y=-\frac{1}{2}x-2+4_{} \\ y=-\frac{x-4}{2} \end{gathered}[/tex]

Then, we will set y = 0 and solve for x to find the x-intercept.

[tex]\begin{gathered} 0=-\frac{x-4}{2} \\ 0=-x-4 \\ 4=-x \\ -x=4 \\ x=-4 \end{gathered}[/tex]

Therefore, the x-intercept is located where y = 0. This means that our coordinate pair will be (-4, 0).

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