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write the equation of the line that passes through the points (-1,-2) and (3,10) in point slope form and slope intercept form

Sagot :

With the points first, we will calculate the slope m

(-1,-2) =(x1,y1)

(3,10)=(x2,y2)

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

then we substitute the values

[tex]m=\frac{10+2}{3+1}=\frac{12}{4}=3[/tex]

the slope is m=3

point-slope form

[tex]y-y_1=m(x-x_1)[/tex]

then we substitute the values and we obtain this form

the point slope form is

[tex]y+2=3(x+1)[/tex]

slope-intercept form

[tex]y=mx+b[/tex]

we clear y of the point-slope form and we obtain the slope-intercept form

[tex]\begin{gathered} y=3x+3-2 \\ y=3x+1 \end{gathered}[/tex]

the slope-intercept form is

y=3x+1

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