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Sagot :
The equation is given as ;
[tex]5a^2-14a=-280[/tex]Divide both terms by 5 as;
[tex]\frac{5a^2}{5}-\frac{14a}{5}=-\frac{280}{5}[/tex]This will give the following;
[tex]a^2-\frac{14}{5}a=\text{ -56}[/tex]Find { b/2}^2 and add it on both sides of the equation where b is the second term in the equation.
{-14/5 / 2 }^2 = {-14/5 * 1/2 }^2 = {-14/10}^2 = {-7/5}^2 = 49/25
Add this on both sides of the equation as;
[tex]a^2-\frac{14}{5}a+\frac{49}{25}=-56+\frac{49}{25}[/tex]Factorize as ;
[tex](a-\frac{7}{5})^2=-54.04[/tex]From the above, you notice, a square-root of a negative number will not result to real solutions for a, thus; the equation has no real solution.
Answer:
No real solution
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