Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Ask your questions and receive precise answers from experienced professionals across different disciplines. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

#10. Find the lateral surface area of the figure discussed in problem 9.#9. Find the volume of a right solid whose height is 2 feet. Dimensions are in feet. (It comes with a picture)

10 Find The Lateral Surface Area Of The Figure Discussed In Problem 99 Find The Volume Of A Right Solid Whose Height Is 2 Feet Dimensions Are In Feet It Comes W class=

Sagot :

Problem 9

The area of a trapezoid is computed using the following formula.

[tex]\text{Area = (}\frac{a+b}{2}\text{)h}[/tex]

In order to use the formula, for this problem

a = 17

b = 14

h = diameter of the half circle = 2*7 = 14

Therefore using the formula for the area of a trapezoid

We have that the area of the trapezoid on the figure would be

[tex](\frac{14+17}{2})14\text{ = 217}[/tex]

Now, the area of the half circle would be

[tex]\text{Half circle = }\frac{\pi\cdot(7)^2}{2}\text{ = }49\pi/2[/tex]

So the area of the base would be

[tex]217+49\pi/2\text{ }[/tex]

And since the solid is a right solid, we just multiply by the height

So, the volume of the right solid would be

[tex]2\cdot(217+49\pi/2\text{ ) = 434 + 49}\cdot\pi[/tex]
View image HooperS360163
View image HooperS360163