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Question 1: Find the measure of side b in the triangle.

Question 1 Find The Measure Of Side B In The Triangle class=

Sagot :

Since we are given a pair and need to find the side of another pair, we use the sine rule.

[tex]\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}[/tex]

One pair is

38 degree angle and opposite side of 13

Another pair [to solve] is

110 degree angle and side 'b' to solve

We substitute into the formula:

[tex]\frac{13}{\sin38}=\frac{b}{\sin 110}[/tex]

We can cross multiply and solve for b. The process is shown below:

[tex]\begin{gathered} 13\times\sin 110=b\times\sin 38 \\ b=\frac{13\sin 110}{\sin 38} \\ b=19.84 \end{gathered}[/tex]

The measure of side b of the triangle shown:

19.84
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