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Sagot :
[tex]Fe_2O_{3(s)}+3C_{(s)}\rightarrow2Fe_{(s)}+3CO_g[/tex]
Firstly we have to convert the mass of the Fe2O3 to moles. We do this using the following equation:
[tex]\begin{gathered} _nFe_2O_{3(g)}=\frac{mass}{molar\text{ }mass} \\ _nFe_2O_{3(g)}=\frac{56.8g}{159.7gmol^{-1}} \\ _nFe_2O_{3(g)}=0.36mol \end{gathered}[/tex]Based on the stichiometric ratio 1 mole of Fe2O3 reacts with 3 moles of carbon. Therefore 0.36 moles of Fe2O3 would react with x moles of carbon. We can determine x:
[tex]\begin{gathered} _nx=3\times0.36mol \\ _nx=1.08mole \end{gathered}[/tex]Now that we have found the moles of carbon reacted, we will now convert this moles to mass:
[tex]\begin{gathered} mass\text{ }C=moles\times molar\text{ }mass \\ mass\text{ }C=1.08\text{ }mol\times12.01\text{ }gmol^{-1} \\ mass\text{ }C=12.97g \end{gathered}[/tex]Mass of carbon required to react with 56.8g of Fe2O3 is 12.97g or 13.0g.
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