Given that
We have some logarithmic values. And we have to find a log value.
Explanation -
The values that are given are
[tex]\begin{gathered} \log_{10}2=0.3010 \\ and \\ \log_{10}36=1.5563 \end{gathered}[/tex]And we have to find the value of
[tex]\log_{10}36^3=?[/tex]So the formula we will use here will be
[tex]\log_{10}a^n=n\times\log_{10}a[/tex]Therefore on using the formula we have
[tex]\begin{gathered} \log_{10}36^3=3\times\log_{10}36 \\ \\ substituting\text{ the value of }\log_{10}36\text{ we have} \\ \\ \log_{10}36^3=3\times1.5563 \\ \log_{10}36^3=4.6689 \end{gathered}[/tex]So the answer is 4.6689
Final answer -
Hence the final answer is 4.6689