Answered

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A survey of 76 randomly selected homeowners find that they spend amount of $68 per month on home maintenance. Construct a 99% confidence interval for the mean amount of money spent per month at home maintenance by all homeowners. Assume that the population standard deviation is $15 per month. Round to the nearest cent

A Survey Of 76 Randomly Selected Homeowners Find That They Spend Amount Of 68 Per Month On Home Maintenance Construct A 99 Confidence Interval For The Mean Amou class=

Sagot :

Explanation:

We will use the following formula to construct the confidence interval:

[tex]\begin{gathered} CI\text{ = }\bar{x}\text{ }\pm\text{ MSE} \\ We\text{ are told that }\bar{x}\text{ = \$68 per month} \end{gathered}[/tex][tex]\begin{gathered} MSE\text{ = z *}\frac{\sigma}{\sqrt{n}} \\ At\text{ a 99\% level of confidence, z = 2.576} \\ We\text{ are given that }\sigma\text{ = \$15 and n = 76} \\ MSE\text{ = 2.576 *}\frac{15}{\sqrt{76}} \\ MSE\text{ = 4.4323....} \end{gathered}[/tex]

Answer:

CI = ($63.57 ; $72.43)

Lower endpoint: $63.57

Upper endpoint: $72.43

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